WBCS.LIVE practice question
Twice the present age of X is 9 years less than the present age Y. The age of X's father P is twice that of X's age and the age of Y is 9 years less than his sister Q's age. If the age of P is 20 years more than the age of Q then find the present age of Y. (in years).
Solve this multiple-choice question and check the correct answer with its explanation below.
Answer options
Correct answer and explanation
Correct answer: 19 years