WBCS.LIVE practice question

Twice the present age of X is 9 years less than the present age Y. The age of X's father P is twice that of X's age and the age of Y is 9 years less than his sister Q's age. If the age of P is 20 years more than the age of Q then find the present age of Y. (in years).

Solve this multiple-choice question and check the correct answer with its explanation below.

Answer options

  1. 23 years
  2. 18 years
  3. 21 years
  4. 19 years

Correct answer and explanation

Correct answer: 19 years