WBCS.LIVE practice question

The percentage increase in the surface area of a cube when each side doubled is

Solve this multiple-choice question and check the correct answer with its explanation below.

Answer options

  1. 25%
  2. 50%
  3. 150%
  4. 300%

Correct answer and explanation

Correct answer: 300%

Explanation: ✅ Correct Answer: D) 300% 📚 Explanation: Surface area of a cube is 6s2. If the side s is doubled (2s), the new area is 6(2s)2 = 24s2. The increase is 24s2 — 6s2 = 18s2. Percentage increase = (18s2 ÷ 6s2) x 100 = 300%