WBCS.LIVE practice question
Let x2, x2, __________, x100 be 100 numbers such that xi + xi+1 = 100 for all i. If x10 = 1, then the value of x1 is
Solve this multiple-choice question and check the correct answer with its explanation below.
Answer options
Correct answer and explanation
Correct answer: 99
Explanation: ā Correct Answer: B) 99 š Explanation: The problem states that the sum of any two consecutive numbers in the series is always 100. If x10 = 1, then x9 + x10 = 100, which means x9 = 99. Similarly, x8 + x9 = 100, so x8 = 1. Following this alternating pattern (1, 99, 1, 99...), all odd-positioned numbers will be 99 and all even-positioned numbers will be 1. Therefore, x1 equals 99.