Find the value of $(1-\frac{1}{3}) (1-\frac{1}{4}) (1-\frac{1}{5}).....(1-\frac{1}{99}) (1-\frac{1}{100})$

Correct answer: .02

Explanation: ✅ Correct Answer: B) .02 📚 Explanation: The mathematical sequence simplifies through cancellation: (2/3) x (3/4) x (4/5) x ... x (99/100). All the numbers from 3 to 99 cancel each other out. Only the first number (2) and the last number (100) are left. The calculation 2 / 100 results in exactly 0.02. This is a basic test of seeing patterns in long products.