According to Stokes' Law, the terminal velocity of a small spherical body falling through a viscous fluid is directly proportional to what?

Correct answer: The square of its radius

Explanation: ✅ Correct Answer: B) The square of its radius 📚 Explanation: Stokes' Law states that the terminal velocity of a sphere falling in a viscous fluid is directly proportional to the square of its radius ($V_t\propto r^2$). This means that a larger drop of water or a heavier spherical object will fall significantly faster through the air or liquid than a smaller one.